Question 971433
In {{{ 25 }}} sec, A has run {{{ 25/45 = 5/9 }}} of a lap
That means B, going in the opposite direction, has
run {{{ 4/9 }}} of a lap.
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So, B's rate is {{{ 4/9 }}} of a lap in {{{ 25 }}} sec
{{{ d = r*t }}}
{{{ 1 = (( 4/9 ) / 25 )*t }}}
{{{ 25 = ( 4/9 )*t }}}
{{{ 225 = 4t }}}
{{{ t = 56.25 }}}
B does 1 lap in 56.25 sec
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check:
{{{ 1 = (( 4/9 ) / 25 )*t }}}
{{{ 1 = (( 4/9 ) / 25 )*56.25 }}}
{{{ 1 = ( .4444 / 25 )*56.25 }}}
{{{ 1 = .01777*56.25 }}}
{{{ 1 = .9999956 }}}
eror due to rounding off