Question 971360
{{{F(x)=x^2-x+1/2-1/2-6}}}
{{{F(x)=(x-1/4)^2-6&1/2}}}
{{{F(x)=(x-1/4)^2-13/2}}}


Inverse would be {{{(y-1/4)^2-13/2=x}}}
{{{(y-1/4)^2=13/2+x}}}
{{{y-1/4=0+- sqrt(13/2+x)}}}
{{{y=1/4+- sqrt(13/2+x)}}}-------Not finished.


Domain for F was {{{x>=1/2}}}.  Now, the RANGE of y is {{{y>=1/2}}}; and the upper branch of y is what is wanted:


{{{highlight(y=1/4+sqrt(13/2+x))}}};
Also the needed domain for x is {{{x>=-13/2}}} to stay within real numbers.