Question 971416
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O=Osei's age=12yrs; F=Father's age=38yrs; x=years until father is twice as old
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F+x=2(O+x) Plug in values.
38yrs+x=2(12yrs+x)
38yrs+x=24yrs+2x Subtract (24yrs+x) from each side.
14yrs=x
ANSWER 1: In 14 years, Father will be twice as old as Osei
ANSWER 2: In 14 years, Osei will be (12yrs+14yrs) 26 years old,
and Father will be (38yrs+14yrs) 52 years old.