Question 82793
find a rational function that has x=-3 and x=5 as vertical asymptotes
So the denominator contains (x+3) and (x-5)
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, y=2 as a horzontal asymptote and (3,0) as an x intercept 
so the numerator conains a factor of 2x^2
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Comment: so far the function looks like 
f(x) = 2x^2/[(x+3)(x-5)]
and (3,0) as an x intercept 
So, it neets a factor of (x-3) in the numerator.
That reduces the need for x^2 in the numerator; x will do the job.

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Final Answer: f(x) = [2x(x-3)]/[(x+3)(x-5)]
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Cheers,
Stan H.
f(x) =