Question 82784
you have the age relationships right, but everyone will be 14 years older when their ages sum to 100


when you multiplied 2h+5+((h+5)/10)=100 by 10 you should have gotten 20h+50+h+5=1000 or 21h+55=1000


if you use the daughter's age as a base, then you avoid the fractions that led to your calculation error


(d+14)+(10d+14)+(10d-5+14)=100 ... 21d+37=100 ... d=3 so w=30 and h=25