Question 971225

Solve the following logarithmic equation

log2(x-4)=4-log2(x+2)
<pre>{{{log (2, (x - 4)) = 4 - log (2, (x + 2))}}}
{{{log (2, (x - 4)) + log (2, (x + 2)) = 4}}}
{{{log (2, (x - 4)(x + 2)) = 4}}} ----- Logarithmic form
{{{(x - 4)(x + 2) = 2^4}}} -------- Exponential form
{{{x^2 - 2x - 8 = 16}}}
{{{x^2 - 2x - 8 - 16 = 0}}}
{{{x^2 - 2x - 24 = 0}}}
(x - 6)(x + 4) = 0
{{{highlight_green(x = 6)}}}  		OR		x = - 4 (ignore)