Question 971258
<pre><b>
Below are all 36 possible rolls of a pair of dice.
The red ones show at least one 2 or 3.  There are 20
of them so the probability of a red one is 20 out of 
36, or {{{20/36}}} which reduces to {{{5/9}}}:


(1,1) <font color="red">(1,2) (1,3)</font> (1,4) (1,5) (1,6)

<font color="red">(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)</font> 

<font color="red">(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)</font> 

(4,1) <font color="red">(4,2) (4,3)</font> (4,4) (4,5) (4,6) 

(5,1) <font color="red">(5,2) (5,3)</font> (5,4) (5,5) (5,6) 

(6,1) <font color="red">(6,2) (6,3)</font> (6,4) (6,5) (6,6) 

Edwin</pre></b>