Question 82784
A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
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NOW DATA:
Let the daughter's age be "x".
Mother age is 10x
Husbands age is 10x-5
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14 Years from now DATA:
Daughter's age will be x+14
Mothers age will be 10x+14
Husbands age will be 10x-5+14 = 10x+9
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EQUATIOn:
x+14 + 10x+14 + 10x+9 = 100
21x+37=100
21x = 63
x=3 (daughter's age NOW)
10x = 30 (mother's age NOW)
10x-5 = 25 (husband's age NOW)
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Cheers,
Stan H.