Question 82784
You are correct in your set up of the problem:

Woman= h+5 
Husband= h 
Daughter=(h+5)/10


However, the equation has to do with the sum of their ages in 14 years.  These are the ages in 14 years:


Woman= h+5 +14
Husband= h +14
Daughter=(h+5)/10  + 14


The equation should be:
(h+5)+14 +(h)+14 +((h+5)/10)+14 =100


Subtract 14*3 = 42 from each side, and your equation will equal 58 instead of 100.  Try that and see if it works.  I think you may have had another error as well:

(h+5) +(h) +((h+5)/10) =58
2h+5 + (h+5)/10 = 58
20h + 50 + h+5 = 580
21h + 55 = 580
21h = 525
h= 525/21 = 25 years old = Husband
w = 30 years old = Wife
d = 30/10= 3 years old = Daughter


In 14 years:
Husband will be 39
Wife will be 44
Daughter will be 17


Check:  39+44+17= 100 years young!!


R^2 at SCC