Question 971175
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The area of the quadrilateral is *[tex \Large 24^2] square inches.  The measure of the hypotenuse, that is the diagonal of the quadrilateral is *[tex \Large 24\sqrt{2}].  The quadrilateral is a square.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \