Question 971185
if f(x)=x^2-7x-4, then the value of f(2x+1)is 
a. 3x^2-18x+3
b. 4x^2+18x-3
c. 4x^2-10x-10
d. x^2+7x-3

Solution:
f(2x+1) = (2x+1)^2-7(2x+1)-4
        = (4x^2 + 4x + 1) - 14x - 7 - 4
        = 4x^2 - 10x - 10
Answer: c. 4x^2-10x-10