Question 971039
Trying to help my pre-calc student--

Solve:

ln(5-x) + ln(3) = ln(6)

THANKS!
<pre>ln (5 - x) + ln 3 = ln 6
ln 3(5 - x) = ln 6 ---- Applying the following: {{{ln (a) + ln (b) = ln (a * b)}}}
3(5 - x) = 6 ---------- Applying the following: {{{ln (c) = ln (6)}}} becomes {{{c = 6}}} 
15 - 3x = 6
- 3x = 6 - 15
- 3x = - 9
x = {{{(- 9)/(- 3)}}}, or {{{highlight_green(x = 3)}}}
Be reminded that you're not finished yet. The value(s) you get for the variable should make the ORIGINAL equation
TRUE, so 3 should be substituted, for x, in the original equation: ln (5 - x) + ln 3 = ln 6, to determine if the
value for x is correct. This is a MUST since there are times when a value may prove to be an EXTRANEOUS solution. 
I'll leave this up to you.