Question 970925
solve the equation for solutions over the interval [0 degrees, 360 degrees). 
2 sin theta - 1 = csc theta
***
2sinx-1=cscx
2sinx-1=1/sinx
lcd: sinx
2sin^2(x)-sinx=1
2sin^2(x)-sinx-1=0
(2sinx+1)(sinx-1)=0
2sinx+1=0
sinx=-1/2
x=210˚, 330˚
or
sinx-1=0
sinx=1
x=90˚