Question 970912
y+x^2=-(8x+23) Write in vertex form and find axis of symmetry
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y = -x^2-8x-23
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y = -(x^2+8x)-23
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-(x^2+8x+16) = y+23-16
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-(x+4)^2 = y+7
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Vetex:: (-4,-7)
Axis of symmetry:: x = -4
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Cheers,
Stan H.