Question 970768
A possible good model for this can be  {{{h(x)=a*x^2}}}.


x_______h
1______129
2______236


{{{system(a*1^2=129,a*2^2=236)}}}


{{{a=129,4a=236}}}
{{{a=59}}}
Not consistent.


Try another model:   {{{h=ax^2+k}}}

{{{system(a*1^2+k=129,a*2^2+k=236)}}}
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{{{system(a+k=129,4a+k=236)}}}
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This one will give {{{highlight(a=107/3)}}} and this can be used in either equation to evaluate k.