<PRE><B>Question 970783</B>
30 coins

Look at 4 dimes, 3 nickels and 1 quarter as if they were done in that order.

(7/30)*(6/29*(5/28)*(4/27)*(5/26)*(4/25)*(3/24)*(10/23).

Now suppose they were done in opposite order, quarters first.
(10/30)*(5/29)*(4/28)*(3/27)*(7/26)*(6/25)*(5/24)*(4/23).

Note that the denominators are the same.  So are the numerators.  How many different ways are these formed?
Dimes 7C4=35   Nickels 5C3=10  Quarters=10    The product of these 3 is 3500.

The numerator product is 504000*3500

The denominator product is 2.36 * E11; divide top and bottom 

Probability=0.0075

While it seems low, the probability of getting  exactly 1 quarter is
(10/30)*(20/29)*(19/28)*(18/27)*(17/26)*(16/25)*(15/24)*(14/23) *10
only 0.16

For 3 nickels out of 30 coins when there are only 5, it is lower, and that has to be multiplied by 0.16.

Then we still have to deal with dimes.
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