Question 970774
The equation is in standard form and you can read the point for vertex and axis of symmetry.  The graph is a parabola opening downward and has vertex at a maximum.


{{{y=-3(x+2)^2+4}}}
A parabola with equation in standard form {{{y=a(x-h)^2+k}}} has vertex (h,k) and axis of symmetry is {{{x=h}}}.


y-intercept?  Let x=0 and solve for y.