Question 970669
 solve:
log2(3x+2)-log2(x)/log2(4) = 3
log2[(3x+2)/x] = log2(64)
-----
(3x+2)/x = 64
61x = 2
x = 2/61
-----------------
3log2(x-1)+log2(4) = 5
log2[(x-1)^3*4] = 5
------
4(x-1)^3 = 2^5
(x-1)^3 = 2^3
x-1 = 2
x = 3
----------------
Logx(1/27) = 3
x^3 = 1/27
x = 1/3
-------------------
5^(1-2x) = 1/5
5^(1-2x) = 5^-1
1-2x = -1
2x = 2
x = 1
-----------------
Cheers,
Stan H.
-----------------