Question 970639

solve the equation.
log 1/5(x^2+x)- log 1/5(x^2-x)=-1
<pre>If {{{1/5}}} is the base, or if the setup is: {{{log (1/5, (x^2 + x)) - log (1/5, (x^2 - x)) = - 1}}}, then {{{highlight_green(system(x = (3/2)_or,x = 1.5))}}}