Question 970532
{{{(x-h)^2+(y-k)^2=r^2}}}

Determine the radius of the circle.
({{{-11}}},{{{6}}})  Is the circumference of the circle => ({{{-11}}},{{{6}}})  could be only one point on the circle

if ({{{-5}}},{{{2}}}) is the center of the circle and and ({{{-11}}},{{{6}}})  one point on the circle, then radius is the distance ({{{d=r}}}) between the center and the point
use distance formula to find the radius:

*[invoke distance_formula -11, 6, -5, 2]

so, in formula for a circle we need radius squared and it is {{{r=52}}}

then, from the coordinates of the center we know that {{{h=5}}} and {{{k=-2}}} and your standard formula is:

{{{(x-5)^2+(y+2)^2=52}}}

{{{drawing( 600, 600, -20, 20, -20, 20,
circle(-11,6,.13),circle(-5,2,.13),locate(-5,2,C(-5,2)),circle(-5,2,2sqrt(13)),
 graph( 600, 600, -20, 20, -20, 20, 0)) }}}