Question 970418
When {{{t=0}}},
{{{R(0)=8-3/(2(0)+4)=8-3/4=32/4-3/4=29/4}}}
(0,31/4)
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When {{{R=0}}},
{{{0=8-3/(2t+4)}}}
{{{3/(2t+4)=8}}}
{{{3=8(2t+4)}}}
{{{3=16t+32}}}
{{{16t=-29}}}
{{{t=-29/16}}}
(-29/16,0)
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Domain is all values except when the denominator equals zero since division by zero is undefined.
{{{2t+4=0}}}
{{{2t=-4}}}
{{{t=-2}}}
Domain:({{{-infinity}}},{{{-2}}})U({{{-2}}},{{{infinity}}})
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*[illustration dcx3.JPG].