Question 970330
x^2+y^2=1  Domain is [-1,1} Range is [-1,1]
x+y=-1; y=-x-1; y^2=x^2+2x+1
x^2+x^2+2x+1=1
2x^2+2x=0
divide by 2
x^2 + x=0
x(x+1)=0
x=0, -1

Points are (-1.0) and (0.-1)




{{{graph(300,200,-3,3,-3,3,sqrt(1-x^2),-sqrt(1-x^2),-1-x)}}}