Question 970330
{{{y=-x-1}}}
;
{{{x^2+(-x-1)^2=1}}}
{{{x^2+x^2+2x+1=1}}}
{{{2x^2+2x=0}}}
{{{x^2+x=0}}}
{{{x(x+1)=0}}}


{{{x=0}}}  or  {{{x=-1}}}.


Resulting points would be  (0,-1)  and  (-1,0).