Question 970199
positive interger = x
other integer = y


A positive integer is 8 more than 15 times another.
{{{x=8+15y}}}
Their product is 272.
{{{xy=272}}}
Now use the first equation to solve for b in the second
{{{x=8+15y}}}
{{{xy=272}}}
{{{(8+15y)y=272}}}
{{{8y+15y^2=272}}}
{{{15y^2+8y-272=0}}}
use the quadratic formula to find the values for y.


a=15
b=8
c=-272
{{{(-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{(-8 +- sqrt( 8^2-4*15*(-272) ))/(2*15) }}}
{{{(-8 +- sqrt( 16384 ))/(30) }}}
{{{(-8 +- 128)/30}}}

y can be either 4 or -4.5.
But the correct value for y is 4.
the reason for this is because the first value is positive.
the product of the 2 numbers (x and y) is a positive 272. so y would have to be positive for this to be true.

to find x, use the second equation.
{{{xy=272}}}
{{{x*4=272}}}
{{{x=68}}}

x is 68 and y is 4.


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