Question 970265

{{{3x^2+40x-128=0}}}....write {{{40x}}} as {{{-8x+48x}}}

{{{3x^2-8x+48x-128=0}}}...group

{{{(3x^2-8x)+(48x-128)=0}}}

{{{x(3x-8)+16(3x-8)=0}}}

{{{(x+16)(3x-8) = 0}}}

solutions:

if {{{(x+16) = 0}}}, then {{{x=-16}}}
if {{{(3x-8) = 0}}}, then {{{x=8/3}}}


{{{ graph( 600, 600, -20, 20, -130, 20,3x^2-8x+48x-128) }}}