Question 970181
Find all solutions if 0° &#8804; &#952; < 360°. When necessary, round your answers to the nearest tenth of a degree. (Enter your answers as a comma-separated list.) 
sin^2 2&#952; &#8722; 7 sin 2&#952; &#8722; 1 = 0
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sin^2 2&#952; &#8722; 7 sin 2&#952; &#8722; 1 = 0
solve for sin 2&#952; by quadratic formula:
{{{sin 2&#952; = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1, b=-7, c=-1
ans:
sin 2&#952;=7.14 (reject, (-1 < sin 2&#952; < 1))
or
sin 2&#952;=-0.14
2&#952;=188.1&#730;, 352.0&#730; (in quadrants III and IV where sin<0)
&#952;=94.0&#730;, 176.0&#730;