<PRE><B>Question 970109</B>
You invested $10,000 in two accounts, one paying 8% and the other account paying 10% annual interest. At the end of the year, the total interest from these investments was $940. How much was invested at each rate?
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Equation:
interest + interest = interest
0.08*x + 0.10(10000-x) = 940
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8x + 10*10000 - 10x = 94000
-2x = -6000
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x = $3000 (amt. invested at 8%)
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10,000-x = $7,000 (amt. invested at 10%)

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Cheers,
Stan H.
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