<PRE><B>Question 969860</B>
(3/8)+(3/4)+(3/2)+3+...+192
this is a geometric series, the formula for the nth term in a geometric series is
xn = ar^(n-1) where a is the first term and r is the common ratio
in this case a = (3/8) and r = 2, we want to find n for the term 192
192 = (3/8) * 2^(n-1)
2^(n-1) = 512
n = 10
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now we want to find the sum of the first 10 terms of our geometric series
sum = a * ((1-r^n) / (1-r)) = (3/8)*((1-(2^10)) / (1-2)) = 383.625
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