Question 969860
 Find the sum.
(3/8)+(3/4)+(3/2)+3+...+192
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a = (3/8)
r = (3/4)/(3/8) = 2
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Solve::
a*r^n = 192
r^n = 192/(3/8) = 512
2^n = 512
n = 9
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Ans: S= a[r^n -1]/(r-1)
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S(9) = (3/8)[2^9 - 1]/[2-1] = (3/8)[511] = 191 5/8
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Cheers,
Stan H.
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