<PRE><B>Question 82662</B>
find the vertex and x-intercepts of the parabola described by the equation:
y=(x+12)(x-2)
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If you let y=0 you find the x-intercepts at x=-12 and x=2.
The x-value of the vertex is half way between -12 and 2 or
at -5,
The y-value is f(-5)=(-5+12)(-5-2) = 7*-7 = -49
Vertex at (-5,-49)
{{{graph(400,300,-15,10,-55,10,(x+12)(x-2))}}}
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Cheers,
Stan H.</PRE>