Question 969743
Leg 1 is X meters (all units are meters)
Leg 2 is X+4
Hypotenuse is (2X-4)  Twice the length of shorter leg minus 4

Pythagorean Theorem
X^2  + (X+4)^2= (2X-4)^2

X^2 +(X+4)(X+4)=(2X-4)(2X-4)

X^2 + X^2 + 8X +16= 4X^2-16X+16

Move terms to right by subtracting 2 X^2 + 8X +16 from both sides.

0= 2X^2 -24 X    The 16s cancel each other.

2X(X-12)=0  Factoring.

X=0 (no sense)

X-12=0 ;  X=12

Leg 1 is 12
Leg 2 is 16

Leg 3 is twice Leg 1 (24) - 4=20

This is a 12:16:20 right triangle,  4 times each side of a 3:4:5.