Question 969732
Let x,y,z be first 3 term of AP.since x,y,z are in AP

y=(x+z)/2 => 2y = x+z-------(1)
Given that,
 x+y+z=15-----------(2)
xyz=45-------(3)
Now substituting (1) in (2)
3y=15=>y=15/3=5
y=5
substituting y=5 in (2)
x+z=10=>x=10-z-----(4)Now again substituting y=5 &(4) in (3)
(10-z)5(z)=45
5z^2-50z+45=0
z^2-10z+9=0
After solving,we get two values for z=1,9
when z=1,then x=9
when z=9,then x=1