Question 969647

Im not sure if this question belongs in this section so please forgive me if it isn't but I just don't know where to start with this equation. 

"Find the equation of the line through (1,3) that is parallel to the line 6x+10y+1=0"

Please help me with step by step action because as you can probably tell I have no idea what to do, and a teacher who speeds way past my ability to comprehend. Thank you in advance, the help is much appreciated.
<pre>y = mx + b ------- Slope-intercept form of a linear equation
(x, y) being a point on the line, m is the slope, and b is the y-intercept

Your equation: 6x + 10y + 1 = 0
10y + 1 = - 6x ------ Subtracting 6x
10y = - 6x - 1 ------ Subtracting 1
{{{y = (- 6x)/(10) - 1/10}}}
{{{y = - (3/5)x - 1/10}}}

Slope of above equation: {{{m = - 3/5}}}
Since parallel lines have congruent slopes, slope of new line, or {{{m = - 3/5}}}
Point on line to be formed: (1, 3)
{{{y - y[1] = m(x - x[1])}}} ------ Point-slope form
{{{y - 3 = (- 3/5)(x - 1)}}} ------ Substituting values
{{{y - 3 = (- 3/5)x + 3/5}}}
{{{y = (- 3/5)x + 3/5 + 3}}} ------ Adding 3 to both sides
{{{y = (- 3/5)x + 3/5 + 15/5}}}
{{{highlight_green(y = (- 3/5)x + 18/5)}}} ----- Equation being sought