Question 969646
On a certain day, the temperature was 37 Fahrenheit at 10am and 49 fahrenheit at 1pm. if the temperature rose at a constant rate from 10am to 1pm on that day, what was the temperature at 11am?
<pre>Let x be time, with starting time being x = 0. Then y is the temperature at a particular time of the day
We then get: {{{f(x) = mx + b}}}
Points: (0, 37) and (3, 49)
Slope or m = {{{(37 - 49)/(0 - 3)}}}, or m = 4
{{{y - y[1] = m(x - x[1])}}}
{{{y - 37 = 4(x - 0)}}}
{{{y - 37 = 4x}}}
 
{{{y = 4x + 37}}}, or {{{f(x) = 4x + 37}}} -------- Equation representing temperature at a certain time of the day
Since 11am is the 1st hour, or hour 1 after 10am, then {{{f(x) = 4x + 37}}} becomes: {{{f(1) = 4(1) + 37}}}, or {{{f(1) = 4 + 37}}}.
Therefore, temperature, 1 hour after 10am, or at 11am = {{{highlight_green(41^o)}}}