Question 969626
This is really a beginning calculus problem.
You need the value of the derivative with respect to {{{s}}} of the function {{{V=s^3}}} .
That derivative can ve represented as {{{dV/ds}}} or as {{{"V'"}}} .
For any value of {{{x}}} that derivative (as a function of {{{x}}} ) is
{{{"V'(x)"=3x^2}}} ,
and for {{{x=6}}} , its value is
{{{"V'(6)"=3*6^2=3*36=108}}} .
 
NOTE: The derivative of any power, is the exponent times the power with an exponent that is one unit less.
If {{{f(x)=x^p}}} , then {{{"F'(x)"=p*x^((p-1))}}}