Question 969616
{{{x^2+11x+7=0}}}


The quadratic equation is {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
for this problem {{{a=1}}}, {{{b=11}}}, and {{{c=7}}} 
the equation {{{ax^2+bx+c=0}}} can be used to figure that out


simply plug in the values
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(11) +- sqrt( (11)^2-4*(1)*(7) ))/(2*(1)) }}}
{{{x = (-11 +- sqrt( 121-28 ))/(2) }}}
{{{x = (-11 +- sqrt(93))/(2) }}}


The answer is{{{x = (-11 + sqrt(93))/(2)}}} and {{{x = (-11 - sqrt(93))/(2)}}}


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