Question 969086
You mean TWO kinds instead of TWELVE kinds.


VARIABLES:
j, how much Jamaican Coffee
v, how much Vanilla Bean Coffee


The description of j and v quantities,
10+2*what, ... the description falls apart.


Continuing to try, the mixture is j+v.
{{{j+v=10+2*j}}}, the mixture, IS, ten pounds more, than two times the amount of Jamaican coffee.
Simplify that is some useful way.
{{{j+v-v=10+2j-v}}}
{{{j=10+2j-v}}}
{{{j-2j=10+2j-v-2j}}}
{{{-j=10-v}}}
{{{highlight_green(j=v-10)}}}-----we can work with this.


Back to the fundamental two part mixture problem,


{{{cost/mass=price}}}


{{{((5.4)j+(6.25)v)/(j+v)=190.4/(j+v)}}}


{{{(5.4)j+(6.25)v=190.4}}}  because accounting for cost is really what is best here;


Substitute according to the complicated description part, for j.
{{{highlight_green((5.4)(v-10)+(6.25)v=190.4)}}}
A unsimplified linear equation in just the one variable, v.

...
and you know what to do from that.....?