Question 969390
find out the three nos such that the product of the first and second is 24 second and the third is 48 and that of the first and and third is 32
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let x=1st no.
let y= 2nd no.
let z=3rd no.
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xy=24
yz=48
xz=32
...
y=24/x
y=48/z
24/x=48/z
..
z=32/x
24/x=48/(32/x)
24/x=48x/32
48x^2=24*32=768
x^2=16
x=√16=4
y=24/x=6
z=32/x=8
..
1st no.=4
2nd no.=6
3rd no.=8