Question 969317
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If they meet after 4 hours after having been 400 miles apart, they must be getting closer to each other at a speed of 100 miles per hour, which is to say the SUM of the two cars' speeds must be 100.  So if one car is travelling at *[tex \Large s] miles per hour and the other is going *[tex \Large s\ +\ 20] miles per hour, we know that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s\ +\ (s\ +\ 20)\ =\ 100]


Solve for *[tex \Large s]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \