Question 969308
{{{x^2+y^2=50}}}
{{{y=x^2-1}}}
Substitute,
{{{x^2=y+1}}}
So,
{{{y+1+y^2=50}}}
{{{y^2+y-49=0}}}
{{{y^2+y+1/4=49+1/4}}}
{{{(y+1/2)^2=197/4}}}
{{{y+1/2=0 +- sqrt(197)/2}}}
{{{y=-1/2 +- sqrt(197)/2}}}
Then you can calculate x,
{{{x^2=1/2 +- sqrt(197)/2}}}
{{{x=0 +- sqrt(1/2 +- sqrt(197)/2)}}}
Yes, that's it.