Question 82624
{{{log(a,7x+1) = log(a,4x+16)}}}
This is a test of your reading of equation. It can be
rewritten as
{{{a^n = 7x+1}}} and
{{{a^m = 4x+15}}}
The equation is telling you that n=m, so
{{{7x+1 = 4x+16}}}
{{{3x = 15}}}
{{{x = 5}}} answer