<PRE><B>Question 969245</B>
A circular cone having an altitude of 9m is divided into two segments having the same vertex . if the smaller altitude is 6m , find the ratio of the volume of the small cone to the big cone
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Note: The ratio of the radii of the bases of the two cones is 9:6 or 3/2
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Volume of big cone = (1/3)pi*r^2*9
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Volume of smaller cone = (1/3)pi(2/3 r)^2*6 = (1/3)pi*r^2[(4/9)*6]
= (1/3)pi*r^2[8/3)
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Ans: ratio of volumes = [Vol of small]/[Vol of bigger]
= (8/3)/9 = 8/27 = 8:27
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Cheers,
Stan H.  
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