Question 969250
Write the equation of a line parallel to the given line but passing through the given point.
y=1/4x-2;(8,-1).
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The given equation has slope = 1/4.
Any line parallel to it must have slope = 1/4
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Form of your equation: 
y = mx + b
Solve for "b"::
-1 = (1/4)8 + b
-1 = 2 + b
b = -3
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Ans: y = (1/4)x - 3
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Write the equation of a line perpendicular to the given line but passing through the given point. 
y=-4x-5;(0,-1)
The given equation has slope = -4
Any line perpendicular to it must have slope = 1/4
Form::
y = mx + b
Solve for "b"::
-1 = (1/4)*0 + b
b = -1
Ans: y = (1/4)x - 1
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Cheers,
Stan H.
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