Question 968980
ln (2x-1) = ln 5 - ln (x-5)
ln(2x-1)+ln(x-5)=ln5
ln[(2x-1)(x-5)]=ln5(Since loga+logb=log(ab))
(2x-1)(x-5)=5
2x^2-11x+5=5
2x^2-11x=0
(2x-11)x=0
x=11/2 (Since x cannot be zero)