Question 968863
5x + 9 < 10x &#8722; 1 
subtract 5x from both sides of <
9 < 5x -1
add 1 to both sides of <
10 < 5x
divide both sides of < by 5
2 < x
therefore
x > 2, in interval notation it is (2, +infinity)
here is the red shaded graph
{{{ graph( 300, 200, -10, 10, -10, 10, x > 2) }}}