Question 968704
HOW LONG would it take:


{{{200=100(1.04)^x}}}
{{{2=1.04^x}}}
Pick whichever base you prefer.
{{{ln(2)=ln(1.04^x)}}}
{{{ln(2)=x*ln(1.04)}}}
{{{highlight(x=ln(2)/ln(1.04))}}} which is approximately {{{17&2/3}}} years.


The second question's solution works similarly.