Question 968677

an equation of a line in slope-intercept form is:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is a y-intercept

The horizontal line has {{{y =b}}}( constant) for every value of {{{x}}}. 

since a horizontal line, in your case, passing through ({{{5}}},{{{-1}}}), the equation is {{{y = -1}}}. 

The slope of a horizontal line is {{{m=0}}}, therefore, your equation in slope-intercept form will be:

 {{{y = 0*x -1}}}