Question 968620
Graph the parabola and find its vertex
y=x^2-6x+1
complete the square:
y=(x^2-6x+9)-9+1
y=(x-3)^2-8
vertex: (3, -8)
see graph below:
{{{ graph( 300, 200, -10, 10, -10, 10,x^2-6x+1) }}}