Question 968503
{{{ax+by=1}}}
When {{{y=0}}},{{{x=5}}},
{{{a(5)+b(0)=1}}}
{{{a=1/5}}}
When {{{x=0}}},{{{y=6}}},
{{{a(0)+b(6)=1}}}
{{{b=1/6}}}
So,
{{{x/5+y/6=1}}}
{{{6x+5y=30}}}
{{{5y=-6x+30}}}
{{{y=-(6/5)x+6}}}
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{{{y=5x-6}}}