Question 82599
Square root(3)/(square root 3 + square root 2)
:
Multiply by the conjugate of the denominator over itself (=1)
{{{sqrt(3)/(sqrt(3) + sqrt(2))}}} * {{{(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))}}} = {{{(3 - sqrt(3*2))/(3 - 2)}}} = {{{(3 - sqrt(6))/(1)}}} = {{{3 - sqrt(6)}}}